0=4x^2+29x-60

Solution for 0=4x^2+29x-60 equation:

0=4x^2+29x-60

We move all terms to the left:

0-(4x^2+29x-60)=0

We add all the numbers together, and all the variables

-(4x^2+29x-60)=0

We get rid of parentheses

-4x^2-29x+60=0

a = -4; b = -29; c = +60;
Δ = b2-4ac
Δ = -292-4·(-4)·60
Δ = 1801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-\sqrt{1801}}{2*-4}=\frac{29-\sqrt{1801}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+\sqrt{1801}}{2*-4}=\frac{29+\sqrt{1801}}{-8}
$